Subjects algebra

Line Solutions 3F24B7

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1. The problem is to determine which ordered pairs satisfy the equation $$y = -\frac{3}{4}x - \frac{1}{2}$$. 2. To check if a point $ (x, y) $ is a solution, substitute $x$ and $y$ into the equation and see if the equality holds. 3. Check each point: - For $(2, -2)$: $$y = -2$$ $$-\frac{3}{4} \times 2 - \frac{1}{2} = -\frac{3}{2} - \frac{1}{2} = -2$$ The point satisfies the equation. - For $(0, -4)$: $$y = -4$$ $$-\frac{3}{4} \times 0 - \frac{1}{2} = 0 - \frac{1}{2} = -\frac{1}{2}$$ The point does not satisfy the equation. - For $(-2, 6)$: $$y = 6$$ $$-\frac{3}{4} \times (-2) - \frac{1}{2} = \frac{3}{2} - \frac{1}{2} = 1$$ The point does not satisfy the equation. - For $(6, -5)$: $$y = -5$$ $$-\frac{3}{4} \times 6 - \frac{1}{2} = -\frac{18}{4} - \frac{1}{2} = -4.5 - 0.5 = -5$$ The point satisfies the equation. - For $(-6, 4)$: $$y = 4$$ $$-\frac{3}{4} \times (-6) - \frac{1}{2} = \frac{18}{4} - \frac{1}{2} = 4.5 - 0.5 = 4$$ The point satisfies the equation. - For $(5, 0)$: $$y = 0$$ $$-\frac{3}{4} \times 5 - \frac{1}{2} = -\frac{15}{4} - \frac{1}{2} = -3.75 - 0.5 = -4.25$$ The point does not satisfy the equation. 4. Therefore, the points that are solutions are $(2, -2)$, $(6, -5)$, and $(-6, 4)$. Final answer: $(2, -2)$, $(6, -5)$, and $(-6, 4)$ are solutions to the equation.