Subjects algebra

Line Table Dca4C5

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1. **State the problem:** We need to complete the table for the equation $y = x + 3$ by finding the values of $y$ for given $x$ values. 2. **Formula:** The equation is $y = x + 3$. This means for each $x$, add 3 to get $y$. 3. **Calculate values:** - For $x = -2$, $y = -2 + 3 = 1$ - For $x = -1$, $y = -1 + 3 = 2$ - For $x = 0$, $y = 0 + 3 = 3$ - For $x = 1$, $y = 1 + 3 = 4$ - For $x = 2$, $y = 2 + 3 = 5$ - For $x = 3$, $y = 3 + 3 = 6$ 4. **Complete the table:** | x | -2 | -1 | 0 | 1 | 2 | 3 | |---|----|----|---|---|---|---| | y | 1 | 2 | 3 | 4 | 5 | 6 | 5. **Graphing notes:** The graph of $y = x + 3$ is a straight line with slope 1 and y-intercept 3. On a coordinate grid with $x$ from -2 to 3 and $y$ from -1 to 7, plot the points from the table and connect them with a straight line. **Final answer:** The completed table is $\{(-2,1), (-1,2), (0,3), (1,4), (2,5), (3,6)\}$ and the graph is a straight line passing through these points.