1. **Problem statement:** Solve the equation $12x - 3 = 8x + 1$ for $x$.
2. **Formula and rules:** To solve linear equations, we isolate the variable $x$ by performing the same operations on both sides of the equation.
3. **Step 1:** Subtract $8x$ from both sides:
$$12x - 3 - 8x = 8x + 1 - 8x$$
which simplifies to
$$12x - \cancel{8x} - 3 = \cancel{8x} + 1$$
$$4x - 3 = 1$$
4. **Step 2:** Add 3 to both sides:
$$4x - 3 + 3 = 1 + 3$$
$$4x = 4$$
5. **Step 3:** Divide both sides by 4:
$$\frac{4x}{\cancel{4}} = \frac{4}{\cancel{4}}$$
$$x = 1$$
**Final answer:**
$$x = 1$$
Linear Equation 07Cdf4
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