1. Let's start with a simple linear equation word problem: "If you buy 3 notebooks and each notebook costs $x, and you pay a total of 15, what is the cost of one notebook?" 2. The formula to use here is the linear equation: $$3x = 15$$ where $x$ is the cost of one notebook. 3. To solve for $x$, divide both sides of the equation by 3: $$\frac{\cancel{3}x}{\cancel{3}} = \frac{15}{3}$$ 4. Simplifying, we get: $$x = 5$$ 5. So, the cost of one notebook is 5. This is a basic example of a linear equation word problem where you translate a real-world situation into an algebraic equation and solve for the unknown.