1. **State the problem:** We are given the linear equation $y = 6x + 11$ and want to understand its properties. 2. **Formula and explanation:** This is a linear function of the form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. 3. **Identify slope and intercept:** Here, the slope $m = 6$ means the line rises 6 units vertically for every 1 unit it moves horizontally. 4. **Find the y-intercept:** The y-intercept $b = 11$ is the point where the line crosses the y-axis, at $(0, 11)$. 5. **Find the x-intercept:** Set $y=0$ to find the x-intercept: $$0 = 6x + 11$$ $$6x = -11$$ $$x = \frac{-11}{6}$$ 6. **Summary:** The line crosses the y-axis at $(0, 11)$ and the x-axis at $\left(\frac{-11}{6}, 0\right)$. 7. **No extrema:** Since this is a linear function, it has no maxima or minima. **Final answer:** The line $y = 6x + 11$ has slope 6, y-intercept 11, and x-intercept $-\frac{11}{6}$.