1. The problem is to rewrite the equation $$-3y = 15 - 4x$$ in slope-intercept form, identify the y-intercept and slope, and determine which line corresponds to this equation. 2. The slope-intercept form of a line is $$y = mx + b$$ where $$m$$ is the slope and $$b$$ is the y-intercept. 3. Start by isolating $$y$$ in the given equation: $$-3y = 15 - 4x$$ Divide both sides by $$-3$$: $$y = \frac{15 - 4x}{-3}$$ 4. Simplify the right side by splitting the fraction: $$y = \frac{15}{-3} - \frac{4x}{-3}$$ 5. Simplify each term: $$y = -5 + \frac{4}{3}x$$ 6. Rewrite in slope-intercept form: $$y = \frac{4}{3}x - 5$$ 7. From this, the slope $$m = \frac{4}{3}$$ and the y-intercept $$b = -5$$. 8. The slope is positive, so the line rises from left to right. 9. Among the lines described, Line B is ascending from bottom-left to top-right, matching the positive slope. 10. Therefore, Line B is the graph of the line $$-3y = 15 - 4x$$. Final answers: - Slope-intercept form: $$y = \frac{4}{3}x - 5$$ - Y-intercept: $$-5$$ - Slope: $$\frac{4}{3}$$ - Corresponding line: Line B