1. **Stating the problem:** We want to solve a math problem suitable for a year 8 student. Since no specific problem was given, let's consider a common algebra problem: Solve for $x$ in the equation $2x + 3 = 11$. 2. **Formula and rules:** To solve for $x$, we use the rule of performing the same operation on both sides of the equation to isolate $x$. 3. **Step 1: Subtract 3 from both sides** $$2x + 3 - 3 = 11 - 3$$ $$2x = 8$$ 4. **Step 2: Divide both sides by 2** $$\frac{\cancel{2}x}{\cancel{2}} = \frac{8}{2}$$ $$x = 4$$ 5. **Answer:** The solution is $x = 4$. This means if you substitute $4$ back into the original equation, it balances correctly: $2(4) + 3 = 8 + 3 = 11$. This is a simple linear equation solving process suitable for year 8 students.