1. **State the problem:**
We are given two points $(86,113)$ and $(176,239)$ and need to find the linear equation relating $R$ and $C$ in the form $R = mC + b$.
2. **Calculate the slope $m$:**
The slope formula is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$
Substitute the points:
$$m = \frac{239 - 113}{176 - 86} = \frac{126}{90} = 1.4$$
3. **Find the intercept $b$:**
Use the point-slope form $y = mx + b$ with one point, say $(86,113)$:
$$113 = 1.4 \times 86 + b$$
Calculate:
$$113 = 120.4 + b$$
Solve for $b$:
$$b = 113 - 120.4 = -7.4$$
4. **Write the linear equation:**
$$R = 1.4C - 7.4$$
5. **Solve for $C$ when $R = 100$:**
Set $R=100$:
$$100 = 1.4C - 7.4$$
Add $7.4$ to both sides:
$$100 + 7.4 = 1.4C$$
$$107.4 = 1.4C$$
Divide both sides by $1.4$:
$$C = \frac{107.4}{1.4}$$
Show cancellation:
$$C = \frac{\cancel{107.4}}{\cancel{1.4}} = 76.71$$
**Final answer:**
$$C = 76.71$$
This means when $R=100$, the value of $C$ is approximately $76.71$.
Linear Equation 892Be5
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