1. **State the problem:** Solve the linear equation $4x - 2y + 3 = 0$ for $y$ in terms of $x$. 2. **Rewrite the equation:** We want to isolate $y$ on one side. Start by moving other terms to the right side: $$4x - 2y + 3 = 0 \implies -2y = -4x - 3$$ 3. **Divide both sides by $-2$ to solve for $y$:** $$y = \frac{-4x - 3}{-2}$$ 4. **Simplify the fraction:** $$y = \frac{\cancel{-4}x + \cancel{-3}}{\cancel{-2}} = 2x + \frac{3}{2}$$ 5. **Final answer:** $$y = 2x + \frac{3}{2}$$ This expresses $y$ as a function of $x$ in slope-intercept form, where the slope is 2 and the y-intercept is $\frac{3}{2}$.