1. The problem is to analyze the linear equation $y = -\frac{3}{4}x + 10$ and understand its graph. 2. This is a linear equation in slope-intercept form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. 3. Here, the slope $m = -\frac{3}{4}$ means the line falls 3 units vertically for every 4 units it moves horizontally to the right. 4. The y-intercept $b = 10$ means the line crosses the y-axis at the point $(0, 10)$. 5. To find the x-intercept, set $y=0$ and solve for $x$: $$0 = -\frac{3}{4}x + 10$$ $$\frac{3}{4}x = 10$$ $$x = \frac{10 \times 4}{3} = \frac{40}{3} \approx 13.33$$ 6. So the x-intercept is at $(\frac{40}{3}, 0)$. 7. The line decreases from left to right because the slope is negative. Final answer: The line has slope $-\frac{3}{4}$, y-intercept at $(0,10)$, and x-intercept at $(\frac{40}{3},0)$.