1. Let's solve a random algebra problem: Solve for $x$ in the equation $$2x + 3 = 11$$. 2. The formula to isolate $x$ is to subtract 3 from both sides and then divide both sides by 2. 3. Subtract 3 from both sides: $$2x + 3 - 3 = 11 - 3$$ which simplifies to $$2x = 8$$ 4. Now divide both sides by 2: $$\frac{\cancel{2}x}{\cancel{2}} = \frac{8}{2}$$ which simplifies to $$x = 4$$ 5. Therefore, the solution is $x = 4$. This means when $x$ is 4, the original equation holds true.