1. The original problem is not provided, but I will create a similar algebra problem involving solving a linear equation. 2. Problem: Solve for $x$ in the equation $$3x + 5 = 20$$. 3. Formula and rules: To solve a linear equation, isolate the variable $x$ by performing inverse operations. 4. Step 1: Subtract 5 from both sides: $$3x + 5 - 5 = 20 - 5$$ $$3x = 15$$ 5. Step 2: Divide both sides by 3: $$\frac{3x}{\cancel{3}} = \frac{15}{\cancel{3}}$$ $$x = 5$$ 6. Final answer: $x = 5$. This is a straightforward linear equation solution demonstrating inverse operations and simplification.