Subjects algebra

Linear Equation Ef50Bb

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1. **State the problem:** Solve the equation $5a + b = 16$ for one variable in terms of the other. 2. **Choose a variable to solve for:** Let's solve for $b$ in terms of $a$. 3. **Isolate $b$:** $$5a + b = 16$$ Subtract $5a$ from both sides: $$\cancel{5a} + b - \cancel{5a} = 16 - 5a$$ which simplifies to $$b = 16 - 5a$$ 4. **Interpretation:** This means for any value of $a$, $b$ can be found using $b = 16 - 5a$. 5. **Alternatively, solve for $a$ in terms of $b$:** $$5a + b = 16$$ Subtract $b$ from both sides: $$5a = 16 - b$$ Divide both sides by 5: $$\frac{5a}{\cancel{5}} = \frac{16 - b}{\cancel{5}}$$ which simplifies to $$a = \frac{16 - b}{5}$$ This completes the solution for the first problem.