1. **State the problem:** Solve the equation $2(3x-1)=-6x-2$ and determine what kind of solution it has. 2. **Use the distributive property:** $$2(3x-1) = 2 \times 3x - 2 \times 1 = 6x - 2$$ So the equation becomes: $$6x - 2 = -6x - 2$$ 3. **Add $6x$ to both sides to collect like terms:** $$6x - 2 + 6x = -6x - 2 + 6x$$ $$12x - 2 = -2$$ 4. **Add 2 to both sides to isolate the term with $x$:** $$12x - 2 + 2 = -2 + 2$$ $$12x = 0$$ 5. **Divide both sides by 12 to solve for $x$:** $$x = \frac{0}{12}$$ $$x = 0$$ 6. **Interpretation:** The equation has a single unique solution $x=0$. **Final answer:** The solution is $x=0$, so the equation has one unique solution.