1. **State the problem:** We need to determine which ordered pairs satisfy the linear equation $$y = 6x + 4$$ exactly. 2. **Recall the formula:** For each ordered pair $ (x, y) $, substitute $x$ into the equation and check if the resulting $y$ matches the given $y$. 3. **Check each ordered pair:** - For $ (2, 12) $: $$y = 6(2) + 4 = 12 + 4 = 16 \neq 12$$ so (2, 12) is not a solution. - For $ (3, 22) $: $$y = 6(3) + 4 = 18 + 4 = 22$$ matches exactly, so (3, 22) is a solution. - For $ (4, 20) $: $$y = 6(4) + 4 = 24 + 4 = 28 \neq 20$$ so (4, 20) is not a solution. - For $ (5, 34) $: $$y = 6(5) + 4 = 30 + 4 = 34$$ matches exactly, so (5, 34) is a solution. - For $ (6, 10) $: $$y = 6(6) + 4 = 36 + 4 = 40 \neq 10$$ so (6, 10) is not a solution. 4. **Final answer:** The ordered pairs that satisfy the equation are **(3, 22)** and **(5, 34)**.