1. **State the problem:** Complete the table for the equation $x + 12 = 6y$ and verify the points.
2. **Rewrite the equation in slope-intercept form:**
$$x + 12 = 6y$$
Divide both sides by 6 to solve for $y$:
$$y = \frac{x + 12}{6}$$
Show canceling common factors if any:
$$y = \frac{\cancel{6}x + \cancel{12}}{\cancel{6}}$$
Actually, 12 is not divisible by 6 in the numerator as a term, so rewrite as:
$$y = \frac{x}{6} + 2$$
3. **Use the formula $y = \frac{x}{6} + 2$ to find $y$ for each $x$ in the table:**
- For $x = -12$:
$$y = \frac{-12}{6} + 2 = -2 + 2 = 0$$
- For $x = -6$:
$$y = \frac{-6}{6} + 2 = -1 + 2 = 1$$
- For $x = 0$:
$$y = \frac{0}{6} + 2 = 0 + 2 = 2$$
- For $x = 6$:
$$y = \frac{6}{6} + 2 = 1 + 2 = 3$$
- For $x = 12$:
$$y = \frac{12}{6} + 2 = 2 + 2 = 4$$
4. **Compare with the given table:**
Given $y$ values are $-2, -1, 2, 3, 4$ for $x = -12, -6, 0, 6, 12$ respectively.
Our calculated $y$ values are $0, 1, 2, 3, 4$.
There is a discrepancy for $x = -12$ and $x = -6$ in the given table.
5. **Conclusion:** The correct $y$ values for the given $x$ values using the equation $x + 12 = 6y$ are:
| $x$ | $y$ |
|-----|-----|
| -12 | 0 |
| -6 | 1 |
| 0 | 2 |
| 6 | 3 |
| 12 | 4 |
The points $(-12, -2)$ and $(-6, -1)$ do not satisfy the equation.
**Final answer:** The correct points on the line $x + 12 = 6y$ are $(-12,0), (-6,1), (0,2), (6,3), (12,4)$.
Linear Equation Table Bbc4Bd
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