1. **State the problem:** We are given the equation $x + 12 = 6y$ and need to complete the table of values for $x$ and $y$.
2. **Rewrite the equation to solve for $y$:**
$$x + 12 = 6y$$
Divide both sides by 6:
$$\frac{x + 12}{6} = y$$
Using cancellation notation:
$$y = \frac{\cancel{x} + 12}{\cancel{6}}$$
This means for each $x$, $y = \frac{x + 12}{6}$.
3. **Calculate $y$ for each $x$ value:**
- For $x = -12$: $y = \frac{-12 + 12}{6} = \frac{0}{6} = 0$
- For $x = -6$: $y = \frac{-6 + 12}{6} = \frac{6}{6} = 1$
- For $x = 0$: $y = \frac{0 + 12}{6} = \frac{12}{6} = 2$
- For $x = 6$: $y = \frac{6 + 12}{6} = \frac{18}{6} = 3$
- For $x = 12$: $y = \frac{12 + 12}{6} = \frac{24}{6} = 4$
4. **Complete the table:**
| $x$ | $y$ |
|-----|-----|
| -12 | 0 |
| -6 | 1 |
| 0 | 2 |
| 6 | 3 |
| 12 | 4 |
5. **Explanation:** To find $y$, we isolate it by dividing the entire equation by 6. Then, for each $x$ value, substitute it into the formula $y = \frac{x + 12}{6}$ and simplify.
This method helps you fill in the table and plot the points on the graph easily.
**Final answer:**
| $x$ | $y$ |
|-----|-----|
| -12 | 0 |
| -6 | 1 |
| 0 | 2 |
| 6 | 3 |
| 12 | 4 |
Linear Equation Table F5F37C
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