1. Form linear equations for the given problems: (i) The perimeter of a rectangle is given by the formula $$P = 2(x + y)$$ where $x$ is length and $y$ is breadth. Given $P = 98$, the equation is: $$2(x + y) = 98$$ Simplify: $$\cancel{2}(x + y) = \cancel{2}49$$ $$x + y = 49$$ (ii) Let son's age be $y$, father's age be $x$. Given father's age is 10 years more than twice son's age: $$x = 2y + 10$$ (iii) Let the two numbers be $x$ and $y$. Given one number is 10 more than the other: $$x = y + 10$$ (iv) Let $x$ be cost per kg of apples and $y$ be cost per kg of oranges. Given cost of 2 kg apples and 3 kg oranges is 120: $$2x + 3y = 120$$ 2. Check if $x=0$, $y=3$ is a solution of $3x + 2y - 6 = 0$: Substitute values: $$3(0) + 2(3) - 6 = 0 + 6 - 6 = 0$$ True, so the statement is **True**. 3. Check if $x=2$, $y=5$ is a solution of $5x + 2y = 10$: Substitute values: $$5(2) + 2(5) = 10 + 10 = 20 \neq 10$$ False, so the statement is **False**.