1. The problem is to find the function $F(x)$ of a straight line given points on the graph and the options for coefficients are limited to -5, -2, 2, or 5 for both slope and intercept. 2. The graph passes approximately through points $(0,10)$ and $(8,-10)$. 3. The slope formula is $m=\frac{y_2-y_1}{x_2-x_1}$. 4. Calculate the slope: $$m=\frac{-10-10}{8-0}=\frac{-20}{8}=-\frac{5}{2}=-2.5$$ 5. The slope $-2.5$ is not exactly one of the options, but the closest is $-2$. 6. The y-intercept is the value of $y$ when $x=0$, which is approximately $10$. 7. The closest intercept option to $10$ is $5$ (since $10$ is not an option). 8. So the function is approximately: $$F(x)=-2x+5$$ 9. This fits the options given and the general trend of the graph (negative slope, positive intercept). Final answer: $$F(x)=-2x+5$$