1. **State the problem:** We are given the expression $6x + 12$ and asked to analyze it. 2. **Identify the type of function:** The expression $6x + 12$ is a linear function, not a parabola. A parabola is represented by a quadratic function of the form $y = ax^2 + bx + c$. 3. **Rewrite the function:** The function is $y = 6x + 12$. 4. **Find the y-intercept:** Set $x=0$, then $y = 6(0) + 12 = 12$. So the graph intersects the y-axis at $(0,12)$. 5. **Find the x-intercept:** Set $y=0$, then $0 = 6x + 12$ which gives $x = -2$. So the graph intersects the x-axis at $(-2,0)$. 6. **Graph shape:** Since the function is linear with positive slope $6$, the graph is a straight line increasing from left to right, not a parabola. **Final answer:** The function $y = 6x + 12$ is a linear function with y-intercept at $(0,12)$ and x-intercept at $(-2,0)$, not a parabola.