1. The problem is to graph the function $g(x) = 2 + x$ over the domain $-2 < x < 2$. 2. The function $g(x) = 2 + x$ is a linear function with slope 1 and y-intercept 2. 3. The domain restriction means we only consider $x$ values strictly between $-2$ and $2$. 4. To graph, calculate values at key points: - At $x = -2$, $g(-2) = 2 + (-2) = 0$ - At $x = 2$, $g(2) = 2 + 2 = 4$ 5. Since the domain excludes the endpoints, the points at $x = -2$ and $x = 2$ are not included (open circles). 6. The graph is a straight line segment connecting points just greater than $-2$ to just less than $2$. 7. The function can be expressed as $y = 2 + x$ with domain $-2 < x < 2$. Final answer: The graph is the line segment of $y = 2 + x$ for $-2 < x < 2$ with open endpoints at $(-2,0)$ and $(2,4)$.