1. The problem is to graph the system of linear inequalities: $$x + y > -3$$ $$y > \frac{3}{2}x - 1$$ 2. These inequalities represent regions above the lines: - Line 1: $x + y = -3$ (rewritten as $y = -x - 3$) - Line 2: $y = \frac{3}{2}x - 1$ 3. Since both inequalities are strict (greater than), the boundary lines are dashed. 4. The solution region is where the shaded areas above both lines overlap. 5. Among the options described, the first graph correctly shows the overlapping shaded region above both lines with dashed boundaries. Final answer: The first graph is the correct choice.