1. **State the problem:** Determine if the ordered pairs (-1, 0), (-1, 5), and (0, -3) satisfy the system of inequalities: $$y \leq 3x + 4$$ $$y < -2x - 1$$ 2. **Check point (-1, 0):** - Substitute $x = -1$, $y = 0$ into the first inequality: $$0 \leq 3(-1) + 4 = -3 + 4 = 1$$ This is true since $0 \leq 1$. - Substitute into the second inequality: $$0 < -2(-1) - 1 = 2 - 1 = 1$$ This is true since $0 < 1$. Therefore, (-1, 0) satisfies both inequalities. 3. **Check point (-1, 5):** - Substitute $x = -1$, $y = 5$ into the first inequality: $$5 \leq 3(-1) + 4 = -3 + 4 = 1$$ This is false since $5 \leq 1$ is not true. Since the first inequality fails, (-1, 5) is not a solution. 4. **Check point (0, -3) algebraically:** - Substitute $x = 0$, $y = -3$ into the first inequality: $$-3 \leq 3(0) + 4 = 0 + 4 = 4$$ True since $-3 \leq 4$. - Substitute into the second inequality: $$-3 < -2(0) - 1 = 0 - 1 = -1$$ True since $-3 < -1$. Therefore, (0, -3) satisfies both inequalities and is a solution. **Final answers:** - (-1, 0): Yes, it is a solution. - (-1, 5): No, it is not a solution. - (0, -3): Yes, it is a solution.