1. **State the problem:** Solve the inequality $$-4 + 4(4r - 8) \leq 10r - 9 - 6$$ for $r$ and write the answer in simplest form.
2. **Apply the distributive property:** Multiply 4 by each term inside the parentheses.
$$-4 + 4 \times 4r - 4 \times 8 \leq 10r - 9 - 6$$
$$-4 + 16r - 32 \leq 10r - 15$$
3. **Combine like terms on the left side:**
$$(-4 - 32) + 16r \leq 10r - 15$$
$$-36 + 16r \leq 10r - 15$$
4. **Isolate variable terms on one side and constants on the other:** Subtract $10r$ from both sides.
$$-36 + 16r - 10r \leq 10r - 10r - 15$$
$$-36 + \cancel{16r - 10r} \leq \cancel{10r - 10r} - 15$$
$$-36 + 6r \leq -15$$
5. **Add 36 to both sides to isolate the term with $r$:**
$$-36 + 6r + 36 \leq -15 + 36$$
$$\cancel{-36 + 36} + 6r \leq 21$$
$$6r \leq 21$$
6. **Divide both sides by 6 to solve for $r$:**
$$\frac{6r}{\cancel{6}} \leq \frac{21}{\cancel{6}}$$
$$r \leq \frac{21}{6}$$
7. **Simplify the fraction:**
$$r \leq \frac{7}{2}$$
**Final answer:** $$r \leq \frac{7}{2}$$
Linear Inequality 48B961
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