1. **State the problem:** Alana runs and walks a total of at least 25 miles per week. We want to write an inequality representing this situation.
2. **Define variables:** Let $x$ be the number of minutes Alana runs per week, and $y$ be the number of minutes she walks per week.
3. **Speeds given:** Running speed = 6 miles per hour, Walking speed = 3 miles per hour.
4. **Convert minutes to hours:** Since speeds are in miles per hour, convert minutes to hours by dividing by 60. So, running time in hours is $\frac{x}{60}$ and walking time in hours is $\frac{y}{60}$.
5. **Distance formula:** Distance = Speed $\times$ Time.
6. **Write distances:** Distance run = $6 \times \frac{x}{60} = \frac{6x}{60} = \frac{x}{10}$ miles.
Distance walked = $3 \times \frac{y}{60} = \frac{3y}{60} = \frac{y}{20}$ miles.
7. **Total distance inequality:** The total distance run and walked is at least 25 miles, so
$$\frac{x}{10} + \frac{y}{20} \geq 25$$
This is the inequality representing the situation.
**Final answer:**
$$\frac{x}{10} + \frac{y}{20} \geq 25$$
Linear Inequality D2Df62
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