1. **State the problem:** We need to sketch the graph of the linear equation using intercepts for the equation $$y = -2x - 4$$.
2. **Recall the formula and rules:** The equation is in slope-intercept form $$y = mx + b$$ where $$m$$ is the slope and $$b$$ is the y-intercept.
3. **Find the y-intercept:** The y-intercept occurs when $$x=0$$.
$$y = -2(0) - 4 = -4$$
So the y-intercept is at the point $$(0, -4)$$.
4. **Find the x-intercept:** The x-intercept occurs when $$y=0$$.
Set $$y=0$$:
$$0 = -2x - 4$$
Add 4 to both sides:
$$4 = -2x$$
Divide both sides by $$-2$$:
$$\cancel{\frac{4}{-2}} = \cancel{\frac{-2x}{-2}}$$
$$x = -2$$
So the x-intercept is at the point $$(-2, 0)$$.
5. **Plot the intercepts:** Plot the points $$(0, -4)$$ and $$(-2, 0)$$ on the coordinate plane.
6. **Draw the line:** Connect these two points with a straight line. This line represents the graph of $$y = -2x - 4$$.
**Final answer:** The graph is a straight line passing through the points $$(0, -4)$$ and $$(-2, 0)$$ with slope $$-2$$.
Linear Intercepts 2Df8F2
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