Subjects algebra

Linear Intercepts 95C813

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1. **Problem Statement:** We need to sketch the graph of the linear function $f(x) = 2x - 4$ using the $x$-intercept and $y$-intercept. 2. **Formula and Important Rules:** - The $y$-intercept is the point where the graph crosses the $y$-axis, which occurs when $x=0$. - The $x$-intercept is the point where the graph crosses the $x$-axis, which occurs when $f(x) = 0$. 3. **Find the $y$-intercept:** Substitute $x=0$ into the function: $$f(0) = 2(0) - 4 = -4$$ So, the $y$-intercept is at $(0, -4)$. 4. **Find the $x$-intercept:** Set $f(x) = 0$ and solve for $x$: $$0 = 2x - 4$$ Add 4 to both sides: $$4 = 2x$$ Divide both sides by 2: $$x = 2$$ So, the $x$-intercept is at $(2, 0)$. 5. **Summary:** - $y$-intercept: $(0, -4)$ - $x$-intercept: $(2, 0)$ 6. **Graphing:** Plot the points $(0, -4)$ and $(2, 0)$ on the coordinate plane and draw a straight line through them. This line represents the graph of $f(x) = 2x - 4$.