1. **Problem Statement:**
We need to sketch the graph of the linear function $f(x) = 2x - 4$ using the $x$-intercept and $y$-intercept.
2. **Formula and Important Rules:**
- The $y$-intercept is the point where the graph crosses the $y$-axis, which occurs when $x=0$.
- The $x$-intercept is the point where the graph crosses the $x$-axis, which occurs when $f(x) = 0$.
3. **Find the $y$-intercept:**
Substitute $x=0$ into the function:
$$f(0) = 2(0) - 4 = -4$$
So, the $y$-intercept is at $(0, -4)$.
4. **Find the $x$-intercept:**
Set $f(x) = 0$ and solve for $x$:
$$0 = 2x - 4$$
Add 4 to both sides:
$$4 = 2x$$
Divide both sides by 2:
$$x = 2$$
So, the $x$-intercept is at $(2, 0)$.
5. **Summary:**
- $y$-intercept: $(0, -4)$
- $x$-intercept: $(2, 0)$
6. **Graphing:**
Plot the points $(0, -4)$ and $(2, 0)$ on the coordinate plane and draw a straight line through them. This line represents the graph of $f(x) = 2x - 4$.
Linear Intercepts 95C813
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