1. Problem 1: Solve the equation $2x + 3 = 7$. 2. Use the formula for linear equations: $ax + b = c$. 3. Subtract 3 from both sides: $$2x + \cancel{3} - \cancel{3} = 7 - 3$$ $$2x = 4$$ 4. Divide both sides by 2: $$\frac{2x}{\cancel{2}} = \frac{4}{\cancel{2}}$$ $$x = 2$$ 5. Final answer for problem 1: $x = 2$. 1. Problem 2: Solve the quadratic equation $x^2 - 5x + 6 = 0$. 2. Use the quadratic formula or factorization. Here, factorization is simpler. 3. Factor the quadratic: $$x^2 - 5x + 6 = (x - 2)(x - 3) = 0$$ 4. Set each factor equal to zero: $$x - 2 = 0 \Rightarrow x = 2$$ $$x - 3 = 0 \Rightarrow x = 3$$ 5. Final answer for problem 2: $x = 2$ or $x = 3$.