1. The problem asks to create tables of values for each linear relation for $x = 0, -1, -2, -3, -4$ and then graph the lines. 2. The general form of a linear equation is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. 3. For each equation, substitute the given $x$ values to find corresponding $y$ values. 4. a) For $y = 5x - 4$: - When $x=0$, $y=5(0)-4= -4$ - When $x=-1$, $y=5(-1)-4= -5 -4 = -9$ - When $x=-2$, $y=5(-2)-4= -10 -4 = -14$ - When $x=-3$, $y=5(-3)-4= -15 -4 = -19$ - When $x=-4$, $y=5(-4)-4= -20 -4 = -24$ 5. b) For $y = -x$: - When $x=0$, $y=0$ - When $x=-1$, $y=-(-1)=1$ - When $x=-2$, $y=-(-2)=2$ - When $x=-3$, $y=-(-3)=3$ - When $x=-4$, $y=-(-4)=4$ 6. c) For $y = 2 + x$: - When $x=0$, $y=2+0=2$ - When $x=-1$, $y=2+(-1)=1$ - When $x=-2$, $y=2+(-2)=0$ - When $x=-3$, $y=2+(-3)=-1$ - When $x=-4$, $y=2+(-4)=-2$ 7. d) For $y = 1 - 4x$: - When $x=0$, $y=1-4(0)=1$ - When $x=-1$, $y=1-4(-1)=1+4=5$ - When $x=-2$, $y=1-4(-2)=1+8=9$ - When $x=-3$, $y=1-4(-3)=1+12=13$ - When $x=-4$, $y=1-4(-4)=1+16=17$ These tables can be used to plot the points and draw the lines on the coordinate planes as described. Final answer: Tables of values for each linear relation are computed as above for $x=0,-1,-2,-3,-4$.