1. **State the problem:** Solve the system of linear equations:
$$4x + 8y = 20$$
$$-4x + 2y = -30$$
2. **Formula and rules:** We can solve this system using the elimination method by adding or subtracting equations to eliminate one variable.
3. **Add the two equations to eliminate $x$:**
$$\begin{aligned}
&(4x + 8y) + (-4x + 2y) = 20 + (-30) \\
&4x - 4x + 8y + 2y = -10 \\
&0 + 10y = -10 \\
&10y = -10
\end{aligned}$$
4. **Solve for $y$:**
$$y = \frac{-10}{10} = -1$$
5. **Substitute $y = -1$ into the first equation to find $x$:**
$$4x + 8(-1) = 20$$
$$4x - 8 = 20$$
$$4x = 20 + 8$$
$$4x = 28$$
6. **Divide both sides by 4:**
$$x = \frac{28}{4}$$
$$x = 7$$
7. **Final answer:**
$$\boxed{(x, y) = (7, -1)}$$
Linear System 11706F
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