1. **State the problem:** Solve the linear system: $$3x + 4y = 72.1/2x + 2y = -2$$ 2. **Rewrite the system clearly:** $$3x + 4y = 72.1$$ $$2x + 2y = -2$$ 3. **Use the substitution or elimination method. Here, we use elimination.** 4. Multiply the second equation by 2 to align coefficients of $y$: $$2 \times (2x + 2y) = 2 \times (-2)$$ $$4x + 4y = -4$$ 5. Subtract the first equation from this new equation: $$\cancel{4x} + 4y - (3x + 4y) = -4 - 72.1$$ $$4x + 4y - 3x - 4y = -76.1$$ $$x = -76.1$$ 6. Substitute $x = -76.1$ into the second original equation: $$2(-76.1) + 2y = -2$$ $$-152.2 + 2y = -2$$ 7. Solve for $y$: $$2y = -2 + 152.2$$ $$2y = 150.2$$ $$y = \frac{150.2}{2}$$ $$y = 75.1$$ **Final answer:** $$x = -76.1, \quad y = 75.1$$