1. **State the problem:** Solve the system of linear equations: $$3x + y = -16$$ $$y = -x - 4$$ 2. **Use substitution method:** Since the second equation gives $y$ in terms of $x$, substitute $y = -x - 4$ into the first equation. 3. **Substitute and simplify:** $$3x + (-x - 4) = -16$$ $$3x - x - 4 = -16$$ $$2x - 4 = -16$$ 4. **Isolate $x$:** $$2x - 4 + 4 = -16 + 4$$ $$2x = -12$$ 5. **Divide both sides by 2:** $$\cancel{2}x = \cancel{2} \times -6$$ $$x = -6$$ 6. **Find $y$ by substituting $x$ back into $y = -x - 4$:** $$y = -(-6) - 4$$ $$y = 6 - 4$$ $$y = 2$$ 7. **Final answer:** The solution to the system is $$\boxed{(x, y) = (-6, 2)}$$