1. **State the problem:** We are given two equations:
$$x = 4y$$
$$x + y = 12$$
We want to find the values of $x$ and $y$ that satisfy both equations simultaneously.
2. **Use substitution method:** Since the first equation gives $x$ in terms of $y$, we can substitute $x = 4y$ into the second equation.
3. **Substitute and simplify:**
$$4y + y = 12$$
$$5y = 12$$
4. **Solve for $y$:**
$$y = \frac{12}{5}$$
5. **Substitute $y$ back to find $x$:**
$$x = 4y = 4 \times \frac{12}{5} = \frac{48}{5}$$
6. **Interpret the solution:**
The solution is $x = \frac{48}{5}$ and $y = \frac{12}{5}$. This means the number of free throws made is $\frac{48}{5}$ and the number of two point shots made is $\frac{12}{5}$.
7. **Why might the answer be considered wrong?**
If the problem expects integer values (since you can't make a fraction of a shot), then the fractional answers indicate no integer solution satisfies both equations exactly. You might need to check if the problem expects integer solutions or if there was a misunderstanding in the problem setup.
**Summary:** We solved the system by substitution and found $x = \frac{48}{5}$ and $y = \frac{12}{5}$.
Linear System 736632
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