Subjects algebra

Linear System 736632

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1. **State the problem:** We are given two equations: $$x = 4y$$ $$x + y = 12$$ We want to find the values of $x$ and $y$ that satisfy both equations simultaneously. 2. **Use substitution method:** Since the first equation gives $x$ in terms of $y$, we can substitute $x = 4y$ into the second equation. 3. **Substitute and simplify:** $$4y + y = 12$$ $$5y = 12$$ 4. **Solve for $y$:** $$y = \frac{12}{5}$$ 5. **Substitute $y$ back to find $x$:** $$x = 4y = 4 \times \frac{12}{5} = \frac{48}{5}$$ 6. **Interpret the solution:** The solution is $x = \frac{48}{5}$ and $y = \frac{12}{5}$. This means the number of free throws made is $\frac{48}{5}$ and the number of two point shots made is $\frac{12}{5}$. 7. **Why might the answer be considered wrong?** If the problem expects integer values (since you can't make a fraction of a shot), then the fractional answers indicate no integer solution satisfies both equations exactly. You might need to check if the problem expects integer solutions or if there was a misunderstanding in the problem setup. **Summary:** We solved the system by substitution and found $x = \frac{48}{5}$ and $y = \frac{12}{5}$.