1. **State the problem:** Solve the system of linear equations: $$-4x + y = -4$$ $$y = 2x + 2$$ 2. **Use substitution method:** Since the second equation is already solved for $y$, substitute $y = 2x + 2$ into the first equation. 3. **Substitute and simplify:** $$-4x + (2x + 2) = -4$$ Simplify the left side: $$-4x + 2x + 2 = -4$$ $$-2x + 2 = -4$$ 4. **Isolate $x$:** $$-2x + 2 = -4$$ Subtract 2 from both sides: $$-2x + \cancel{2} - \cancel{2} = -4 - 2$$ $$-2x = -6$$ Divide both sides by $-2$: $$\frac{-2x}{\cancel{-2}} = \frac{-6}{\cancel{-2}}$$ $$x = 3$$ 5. **Find $y$ by substituting $x=3$ into $y=2x+2$:** $$y = 2(3) + 2 = 6 + 2 = 8$$ 6. **Final answer:** The solution to the system is $$\boxed{(3, 8)}$$ This means the two lines intersect at the point $(3,8)$.