1. **State the problem:** Solve the system of linear equations:
$$\begin{cases} X + Y = 2 \\ X - Y = 4 \end{cases}$$
2. **Use substitution or elimination to solve:**
Add the two equations to eliminate $Y$:
$$ (X + Y) + (X - Y) = 2 + 4 $$
$$ 2X + \cancel{Y} - \cancel{Y} = 6 $$
$$ 2X = 6 $$
Divide both sides by 2:
$$ \cancel{2}X / \cancel{2} = 6 / 2 $$
$$ X = 3 $$
3. **Find $Y$ by substituting $X=3$ into one of the original equations:**
Using $X + Y = 2$:
$$ 3 + Y = 2 $$
Subtract 3 from both sides:
$$ Y = 2 - 3 $$
$$ Y = -1 $$
4. **Solution set:**
$$ (X, Y) = (3, -1) $$
5. **Identify the type of system:**
Since there is a unique solution, the system is **consistent and independent**.
6. **Graphing:**
- The line $X + Y = 2$ can be rewritten as $Y = 2 - X$.
- The line $X - Y = 4$ can be rewritten as $Y = X - 4$.
The two lines intersect at the point $(3, -1)$, confirming the solution.
Linear System D4A13D
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