Subjects algebra

Linear Table B47652

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1. The problem is to complete the table for the function $y = -x - 3$ by calculating the values of $-x$ and $y$ for each given $x$. 2. The formula is $y = -x - 3$. For each $x$, first find $-x$, then substitute into the formula to find $y$. 3. Calculate each row: - For $x = -3$: $-x = -(-3) = 3$, $y = 3 - 3 = 0$ - For $x = -2$: $-x = -(-2) = 2$, $y = 2 - 3 = -1$ - For $x = -1$: $-x = -(-1) = 1$, $y = 1 - 3 = -2$ - For $x = 0$: $-x = -(0) = 0$, $y = 0 - 3 = -3$ - For $x = 1$: $-x = -(1) = -1$, $y = -1 - 3 = -4$ - For $x = 2$: $-x = -(2) = -2$, $y = -2 - 3 = -5$ - For $x = 3$: $-x = -(3) = -3$, $y = -3 - 3 = -6$ 4. The completed table is: | $x$ | $-x$ | $y = -x - 3$ | |-----|------|--------------| | -3 | 3 | 0 | | -2 | 2 | -1 | | -1 | 1 | -2 | | 0 | 0 | -3 | | 1 | -1 | -4 | | 2 | -2 | -5 | | 3 | -3 | -6 | 5. The graph of $y = -x - 3$ is a straight line with slope $-1$ and y-intercept $-3$. It decreases by 1 unit in $y$ for every 1 unit increase in $x$.