1. **State the problem:** Rewrite the linear equation $$20x + 13y = 13$$ in slope-intercept form, which is $$y = mx + b$$ where $$m$$ is the slope and $$b$$ is the y-intercept. 2. **Formula and rules:** To convert from standard form $$Ax + By = C$$ to slope-intercept form, solve for $$y$$: $$By = -Ax + C$$ Then divide both sides by $$B$$: $$y = -\frac{A}{B}x + \frac{C}{B}$$ 3. **Apply to the given equation:** Start with: $$20x + 13y = 13$$ Isolate $$y$$: $$13y = -20x + 13$$ 4. **Divide both sides by 13:** $$y = \frac{-20x + 13}{13}$$ 5. **Split the fraction:** $$y = -\frac{20}{13}x + \frac{13}{13}$$ 6. **Simplify the constant term:** $$y = -\frac{20}{13}x + 1$$ **Final answer:** $$y = -\frac{20}{13}x + 1$$ This is the slope-intercept form with slope $$m = -\frac{20}{13}$$ and y-intercept $$b = 1$$.