1. **State the problem:** A restaurant pays $3.75 per load plus $12.25 for delivery. The weekly budget is 85. We want to find how many loads $x$ can be cleaned without exceeding the budget. 2. **Write the inequality:** Total cost $= 3.75x + 12.25 \leq 85$ 3. **Solve the inequality:** $$3.75x + 12.25 \leq 85$$ Subtract 12.25 from both sides: $$3.75x \leq 85 - 12.25$$ $$3.75x \leq 72.75$$ Divide both sides by 3.75: $$x \leq \frac{72.75}{3.75}$$ $$x \leq 19.4$$ 4. **Interpretation:** Since $x$ represents the number of loads, it must be a whole number. The restaurant can afford at most 19 loads per week within the budget. **Final answer:** $$x \leq 19$$