Subjects algebra

Log 170 Expression 41A054

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1. **State the problem:** We are given that $\log 17 = k$ and need to find an expression for $\log 170$ in terms of $k$. 2. **Recall the logarithm property:** The logarithm of a product is the sum of the logarithms: $$\log(ab) = \log a + \log b$$ 3. **Express 170 as a product:** $$170 = 17 \times 10$$ 4. **Apply the logarithm property:** $$\log 170 = \log(17 \times 10) = \log 17 + \log 10$$ 5. **Substitute the given value and known log:** Since $\log 17 = k$ and $\log 10 = 1$ (common logarithm base 10), $$\log 170 = k + 1$$ **Final answer:** $$\boxed{\log 170 = k + 1}$$