1. The problem asks to evaluate $\log_{0.25} 8$ and match it with one of the given options: (a) $\frac{3}{2}$, (b) $\frac{2}{4}$, (c) $\frac{2}{3}$, (d) $-\frac{3}{2}$.\n\n2. Recall that $\log_a b = x$ means $a^x = b$. Here, $a=0.25$ and $b=8$. We want to find $x$ such that $$0.25^x = 8.$$\n\n3. Express the bases as powers of 2: $0.25 = \frac{1}{4} = 2^{-2}$ and $8 = 2^3$. Substitute these: $$\left(2^{-2}\right)^x = 2^3.$$\n\n4. Simplify the left side using power of a power rule: $$2^{-2x} = 2^3.$$\n\n5. Since the bases are equal, set the exponents equal: $$-2x = 3.$$\n\n6. Solve for $x$: $$x = -\frac{3}{2}.$$\n\n7. Therefore, $\log_{0.25} 8 = -\frac{3}{2}$, which corresponds to option (d).