1. **Problem:** Find the value of $\log_2 32$. 2. **Formula:** The logarithm $\log_b a$ answers the question: "To what power must we raise $b$ to get $a$?" Mathematically, if $\log_b a = x$, then $b^x = a$. 3. **Step-by-step solution:** - We want to find $x$ such that $2^x = 32$. - Since $32 = 2^5$, we have $2^x = 2^5$. - Therefore, $x = 5$. 4. **Answer:** $$\log_2 32 = 5$$ This means 2 raised to the power 5 equals 32.