1. The problem asks for the approximate value of $\log_2 32$. 2. Recall the definition of logarithm: $\log_b a = c$ means $b^c = a$. 3. Here, $b=2$ and $a=32$, so we want to find $c$ such that $2^c = 32$. 4. We know that $2^5 = 32$ exactly. 5. Therefore, $\log_2 32 = 5$. 6. Among the options given, the closest answer is d. 5.