1. The problem is to find $\log 25$. 2. Recall the logarithm property: $\log a^b = b \log a$. 3. Since $25 = 5^2$, we can write $\log 25 = \log 5^2$. 4. Using the property, $\log 5^2 = 2 \log 5$. 5. Therefore, $\log 25 = 2 \log 5$. This expresses $\log 25$ in terms of $\log 5$. Final answer: $\log 25 = 2 \log 5$.