1. The problem is to evaluate the expression $10\log 290$. 2. Recall that $\log$ without a base specified usually means base 10 logarithm. 3. The expression $10\log 290$ means $10$ times the logarithm base 10 of $290$. 4. Using the logarithm property: $a \log b = \log b^a$, we can rewrite: $$10\log 290 = \log 290^{10}$$ 5. This means the expression equals the logarithm base 10 of $290^{10}$. 6. To find the numerical value, calculate $\log 290$ first: $$\log 290 \approx 2.4624$$ 7. Multiply by 10: $$10 \times 2.4624 = 24.624$$ 8. Therefore, the value of $10\log 290$ is approximately $24.624$.