1. The problem is to evaluate $\ln e^{2}$.
2. Recall the logarithm power rule: $\ln a^{b} = b \ln a$.
3. Since $\ln e = 1$, we can simplify:
$$\ln e^{2} = 2 \ln e = 2 \times 1 = 2$$
4. Therefore, the value of $\ln e^{2}$ is 2.
Logarithm Evaluation 74E6Ed
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