1. **State the problem:** Evaluate $\log_{11}{121}$.
2. **Recall the logarithm definition:** $\log_a{b} = c$ means $a^c = b$.
3. **Apply the definition:** We want to find $x$ such that $11^x = 121$.
4. **Express 121 as a power of 11:** $121 = 11^2$.
5. **Substitute:** $11^x = 11^2$.
6. **Since the bases are equal, equate exponents:** $x = 2$.
**Final answer:** $\log_{11}{121} = 2$.
Logarithm Evaluation E3Da48
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