1. **State the problem:** Write as a single logarithm: $$\log_5(x^2) + \log_5(3)$$
2. **Recall the Product Property of Logarithms:** $$\log_a(MN) = \log_a M + \log_a N$$ which means the sum of two logarithms with the same base is the logarithm of the product of their arguments.
3. **Apply the property:**
$$\log_5(x^2) + \log_5(3) = \log_5(x^2 \cdot 3)$$
4. **Simplify the argument:**
$$\log_5(3x^2)$$
5. **Final answer:**
$$\boxed{\log_5(3x^2)}$$
This expresses the sum as a single logarithm using the product property.
Logarithm Product 1E9Ef1
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