1. The problem is to simplify the expression $$\frac{\log(3)}{\log_n(3)}$$ where $\log$ is the logarithm with an unspecified base (commonly base 10) and $\log_n$ is the logarithm with base $n$. 2. Recall the change of base formula for logarithms: $$\log_a(b) = \frac{\log_c(b)}{\log_c(a)}$$ for any positive base $c \neq 1$. 3. Using this formula, we can express $\log_n(3)$ in terms of $\log(3)$ and $\log(n)$ as: $$\log_n(3) = \frac{\log(3)}{\log(n)}$$ 4. Substitute this into the original expression: $$\frac{\log(3)}{\log_n(3)} = \frac{\log(3)}{\frac{\log(3)}{\log(n)}}$$ 5. Simplify the complex fraction by multiplying numerator and denominator: $$= \log(3) \times \frac{\log(n)}{\log(3)}$$ 6. Cancel $\log(3)$ in numerator and denominator: $$= \cancel{\log(3)} \times \frac{\log(n)}{\cancel{\log(3)}} = \log(n)$$ 7. Therefore, the simplified expression is: $$\boxed{\log(n)}$$