1. **State the problem:** Simplify the expression $\log_6 2 + \log_6 9 - \log_6 3$. 2. **Recall the logarithm properties:** - $\log_b a + \log_b c = \log_b (a \times c)$ - $\log_b a - \log_b c = \log_b \left(\frac{a}{c}\right)$ 3. **Apply the addition property:** $$\log_6 2 + \log_6 9 = \log_6 (2 \times 9) = \log_6 18$$ 4. **Apply the subtraction property:** $$\log_6 18 - \log_6 3 = \log_6 \left(\frac{18}{3}\right)$$ 5. **Simplify the fraction:** $$\log_6 \left(\frac{\cancel{18}}{\cancel{3}}\right) = \log_6 6$$ 6. **Evaluate the logarithm:** Since $\log_6 6 = 1$ (because $6^1 = 6$), the expression simplifies to 1. **Final answer:** $$\boxed{1}$$