1. **State the problem:** Simplify the expression $\log_3 28 - \log_3 7$. 2. **Recall the logarithm subtraction rule:** For any positive numbers $a$, $b$, and base $c > 0$, $c \neq 1$, the rule is: $$\log_c a - \log_c b = \log_c \left( \frac{a}{b} \right)$$ This means subtracting logarithms with the same base is equivalent to the logarithm of the quotient. 3. **Apply the rule:** $$\log_3 28 - \log_3 7 = \log_3 \left( \frac{28}{7} \right)$$ 4. **Simplify the fraction:** $$\frac{28}{7} = 4$$ 5. **Final expression:** $$\log_3 4$$ **Answer:** $\log_3 4$ is the simplified form of the original expression. This means the difference of the two logarithms is the logarithm base 3 of 4.